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- //
- // Another useful practice for bit manipulation is setting bits as flags.
- // This is especially useful when processing lists of something and storing
- // the states of the entries, e.g. a list of numbers and for each prime
- // number a flag is set.
- //
- // As an example, let's take the Pangram exercise from Exercism:
- // https://exercism.org/tracks/zig/exercises/pangram
- //
- // A pangram is a sentence using every letter of the alphabet at least once.
- // It is case insensitive, so it doesn't matter if a letter is lower-case
- // or upper-case. The best known English pangram is:
- //
- // "The quick brown fox jumps over the lazy dog."
- //
- // There are several ways to select the letters that appear in the pangram
- // (and it doesn't matter if they appear once or several times).
- //
- // For example, you could take an array of bool and set the value to 'true'
- // for each letter in the order of the alphabet (a=0; b=1; etc.) found in
- // the sentence. However, this is neither memory efficient nor particularly
- // fast. Instead we take a simpler way, very similar in principle, we define
- // a variable with at least 26 bits (e.g. u32) and also set the bit for each
- // letter found at the corresponding position.
- //
- // Zig provides functions for this in the standard library, but we prefer to
- // solve it without these extras, after all we want to learn something.
- //
- const std = @import("std");
- const ascii = std.ascii;
- const print = std.debug.print;
- pub fn main() !void {
- // let's check the pangram
- print("Is this a pangram? {?}!\n", .{isPangram("The quick brown fox jumps over the lazy dog.")});
- }
- fn isPangram(str: []const u8) bool {
- // first we check if the string has at least 26 characters
- if (str.len < 26) return false;
- // we uses a 32 bit variable of which we need 26 bits
- var bits: u32 = 0;
- // loop about all characters in the string
- for (str) |c| {
- // if the character is an alphabetical character
- if (ascii.isASCII(c) and ascii.isAlphabetic(c)) {
- // then we set the bit at the position
- //
- // to do this, we use a little trick:
- // since the letters in the ASCII table start at 65
- // and are numbered sequentially, we simply subtract the
- // first letter (in this case the 'a') from the character
- // found, and thus get the position of the desired bit
- bits |= @as(u32, 1) << @truncate(ascii.toLower(c) - 'a');
- }
- }
- // last we return the comparison if all 26 bits are set,
- // and if so, we know the given string is a pangram
- //
- // but what do we have to compare?
- return bits == 0x..???;
- }
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