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- //
- // The Zig language is in rapid development and continuously improves
- // the language constructs steadily.
- //
- // Since version 0.11, the "for-loops" widely used in other languages
- // such as C, e.g. "for (int i = 0; i < 10..." can now also be formed
- // similarly in Zig, which previously required a "while" construct.
- // Similar in this case actually means better, just as Zig generally
- // tries to make everything simple and "better".
- //
- // These new "for-loops" look like the following in Zig:
- //
- // for (0..10) |idx| {
- // // In this case 'idx' takes all values from 0 to 9.
- // }
- //
- // This is really simple and can replace the previous, somewhat bulky:
- //
- // var idx: usize = 0;
- // while (idx < 10) : (idx += 1) {
- // // Again, idx takes all values from 0 to 9.
- // }
- //
- // This would also simplify exercise 13, for example.
- // The best way to try this out is to use this exercise, which in the
- // original looks like this:
- //
- // ...
- // var n: u32 = 1;
- //
- // // I want to print every number between 1 and 20 that is NOT
- // // divisible by 3 or 5.
- // while (n <= 20) : (n += 1) {
- // // The '%' symbol is the "modulo" operator and it
- // // returns the remainder after division.
- // if (n % 3 == 0) continue;
- // if (n % 5 == 0) continue;
- // std.debug.print("{} ", .{n});
- // }
- // ...
- //
- const std = @import("std");
- // And now with the new "for-loop".
- pub fn main() void {
- // I want to print every number between 1 and 20 that is NOT
- // divisible by 3 or 5.
- for (???) |n| {
- // The '%' symbol is the "modulo" operator and it
- // returns the remainder after division.
- if (n % 3 == 0) continue;
- if (n % 5 == 0) continue;
- std.debug.print("{} ", .{n});
- }
- std.debug.print("\n", .{});
- }
- // Is actually a little easier. The interesting thing here is that the other
- // previous 'while' exercises (11,12, 14) cannot be simplified by this
- // new "for-loop". Therefore it is good to be able to use both variations
- // accordingly.
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